The correct option is B e 1 nbsp;lim _ n →∞ nbsp;∑ _ r =1 ^ n 1 / n e ^ r / n =∫ _ 0 ^ 1 e ^ x dx =[ e ^ x ] nbsp;_ 0 ^ 1 =e 1 ...

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Property 1

limn→∞∑r=1n1/...

Question

$lim n \to \infty n \sum r = 1 \frac{1}{n} e^{r / n}$ is:

e

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e - 1

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1 - e

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e + 1

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Solution

The correct option is B $e - 1$
$lim n \to \infty n \sum r = 1 \frac{1}{n} e^{r / n} = \int_{0}^{1} e^{x} d x = {[e^{x}]}_{0}^{1} = e - 1$

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