$lim n \to \infty \frac{2^{n} - 1}{2^{n} + 1} =$

1

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\frac{1}{2}

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- 1

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0

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Solution

The correct option is A $1$
We divide both the numerator and denominator by $2^{n}$
The expression transforms to,
$l i m_{n \to \infty} \frac{1 - \frac{1}{2^{n}}}{1 + \frac{1}{2^{n}}}$
Applying the limit,
$= \frac{1 - 0}{1 + 0} = 1$
Hence, option 'A' is correct.

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