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Question

limn(n+2)!+(n+1)!(n+2)!(n+1)!=

A
1
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B
1/2
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C
1/2
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D
1/3
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Solution

The correct option is A 1
We divide both the numerator and the denominator, by (n+2)!
On simplyfying we get,

limn1+(n+1)!(n+2)!1(n+1)!(n+2)!

=limn1+1(n+2)11(n+2)

Since, n,1n+20

Applying the limit,

=1+010

=1

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