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Question

limn(1x2+2x2+3x2+....+xx2)

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Solution

=limx(1x2+2x2+3x2+...+xx2)

=limx1x2(1+2+3+.......+x)

=limx1x2×x(x+1)2

=limx1x2×x22(1+1x)

limx12(1+1x)

=12

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