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Question

limx0(1+x)1m(1x)1m(1+x)1n(1x)1n=

A
1
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B
m+nmn
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C
nm
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D
mn
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Solution

The correct option is B nm
Using L-Hospital's rule and substituting x=0, we get
limx01m(1+x)1m1+1m(1x)1m11n(1+x)1n1+1n(1x)1n1=nm

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