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Question

limx0sinxx+16x3x5=1a. Find a

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Solution

limx0sinxx+(1/6)x3x5
=limx0[x(1/3!)x3+(1/5!)x5]x+(1/6)x3x5
=limx01x5[15!x5+higher powers of x]
=limx0[1120+higher powers of x]=1120.
a=120

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