wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

limx1(1x2)1log(1x)=

A
e
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1e
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1e2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
e2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A e
k=limx1(1x2)1log(1x)
Applying log on both the sides,
logk=limx11log(1x)log(1x2)
k=elimx1log(1x2)log(1x)
It is of the form 00, so applying L-Hospital's rule
k=elimx12x(1x2)11x
k=e

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Continuity of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon