Question

$\underset{x\to 1}{lim}\frac{3x^5+5x^{10}-7x^{15}}{11x^{15}-13x^9+17x^4}$=

• A. 3/11
• B. 3/17
• C. 1/15
• D. 1/11

Answer 1

Answer: (C)

1/15

Given, $\underset{x\to 1}{lim}\frac{3x^5+5x^{10}-7x^{15}}{11x^{15}-13x^9+17x^4}$
Substituting $x=1$ in the functions, we get
$\underset{x\to 1}{lim}\frac{3x^5+5x^{10}-7x^{15}}{11x^{15}-13x^9+17x^4}=\frac{3{\left(1\right)}^5+5(1{)}^{10}-7{\left(1\right)}^{15}}{11{\left(1\right)}^{15}-13{\left(1\right)}^9+17{\left(1\right)}^4}=\frac{3+5-7}{11-13+17}=\frac{1}{15}$