Limx- 2a-x-2a-x-2a-x2-4a2 is equal to

The correct option is B 1/2√(a) L=lim_x→ 2a√(x 2a)+√(x) √(2a)/√(x^2 4a^2)=lim_x→ 2a√(x 2a)+√(x) √(2a)/√((x 2a)(x+2a)) =lim_x→ 2a1/√(x+2a)+lim_x→ ...

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Factorization Method Form to Remove Indeterminate Form

limx→ 2a√x-2a...

Question

$lim x \to 2 a \frac{\sqrt{x - 2 a} + \sqrt{x} - \sqrt{2 a}}{\sqrt{x^{2} - 4 a^{2}}}$ is equal to

\frac{1}{\sqrt{a}}

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\frac{1}{2 \sqrt{a}}

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- \frac{1}{a}

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- \frac{1}{2 \sqrt{a}}

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Solution

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Similar questions

l i m x \to 2 a \frac{\sqrt{(x - 2 a)} + \sqrt{x} - \sqrt{2 a}}{\sqrt{(x^{2} - 4 a^{2})}}

\frac{1}{b \sqrt{a}}

I = \int x s i n^{- 1} {\frac{1}{2} \sqrt{\frac{2 a - x}{a}}} d x = \frac{A}{248} (x^{2} - 2 a^{2}) c o s^{- 1} \frac{x}{2 a} - \frac{1}{8} x \sqrt{4 a^{2} - x^{2}} + C

{lim}_{x \to 2 a} \frac{\sqrt{x - 2 a} + \sqrt{x} - \sqrt{2 a}}{\sqrt{x^{2} - 4 a^{2}}}

(2 a + \frac{1}{2 a}) (2 a - \frac{1}{2 a})

4 a^{2} - \frac{1}{4 a^{2}}

{(a + \frac{1}{2 a +} \frac{1}{2 a +} \dots)}^{2} + {(a - \frac{1}{2 a -} \frac{1}{2 a -} \dots)}^{2} = 2 a^{2}

(a + \frac{1}{2 a +} \frac{1}{2 a +} \dots) (a - \frac{1}{2 a -} \frac{1}{2 a -} \dots) = a^{2} - \frac{1}{2 a^{2} -} \frac{1}{2 a^{2} -} \dots

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