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Question

limxax58a58x13a13=

A
158a724
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B
154a724
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C
158a724
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D
154a724
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Solution

The correct option is A 158a724
At x=a numerator and denominator becomes zero.
Using L-Hospital's rule, we get:
=limxa[(5/8)x3/8][(1/3)x2/3]

=(15/8)a7/24

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