The correct option is B a2
Simplifying the expression in brackets by setting a1/4=b and x1/4=y, the function whose limit is required can be written as
⎧⎪⎨⎪⎩⎡⎣(b2+y2b−y)−1−2byy3−by2+b2y−b3⎤⎦−1−212log4b4⎫⎪⎬⎪⎭8
=⎧⎨⎩[b−yb2+y2−2by(y−b)(b2+y2)]−1−b⎫⎬⎭8
={[1b−y−b]}8=y8=x2
Hence the required lim as x→a is a2