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Question

limxa(a1/2+x1/2a1/4x1/4)12(ax)1/4x3/4a1/4x1/2+a1/2x1/4a3/42log4a8is

A
a
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B
a3/4
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C
a2
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D
none of these
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Solution

The correct option is B a2
Simplifying the expression in brackets by setting a1/4=b and x1/4=y, the function whose limit is required can be written as
(b2+y2by)12byy3by2+b2yb31212log4b48
=[byb2+y22by(yb)(b2+y2)]1b8
={[1byb]}8=y8=x2
Hence the required lim as xa is a2

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