The correct option is D 2The given expression can be written in the form of, nbsp; 2xsin x πcos x Since, on applying the limit, the function is of the ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Evaluation of a Determinant

limx→π/22xtan...

Question

$lim x \to \frac{π}{2} (2 x tan x - \frac{π}{cos x}) =$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D -2
The given expression can be written in the form of, $\frac{2 x s i n x - π}{c o s x}$
Since, on applying the limit, the function is of the form $\frac{0}{0}$
We apply L-Hospital Rule and divide the numerator and the denominator individually.
$l i m_{x \to \frac{π}{2}} \frac{2 x c o s x + 2 s i n x}{- s i n x}$
We now apply the limit to get the answer as $- 2$

Suggest Corrections

Similar questions

Q. The

lim x \to \frac{π}{2} {2 x tan x - \frac{π}{cos x}}

is:

${lim}_{x \to \frac{π}{2}} \frac{2^{- cos x} - 1}{x (x - \frac{π}{2})}$

l i m_{x \to π} \frac{\sqrt{2 + cos x - 1}}{{(π - x)}^{2}}

{lim}_{x \to \frac{π}{2}} \frac{2^{- cos x} - 1}{x (x - \frac{π}{2})}

Q. Solve

lim x \to \frac{π}{2} \frac{2^{- cos x - 1}}{x (x - \frac{π}{2})}

Join BYJU'S Learning Program

limx→π2(2xtanx−πcosx)=

$lim x \to \frac{π}{2} (2 x tan x - \frac{π}{cos x}) =$