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Question

limxπ2acotxacosxcotxcosx=

A
loga
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B
log2
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C
a
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D
logx
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Solution

The correct option is A loga
First we take acosx common from the numerator, the limit becomes

limxπ2acosx[acotxcosx1cotxcosx]

Let y=cotxcosx

As xπ2,y0

This is of the form,

limxπ2acosx×limy0[ay1y]

=1×loga

=loga

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