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B
1
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C
0
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D
3
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Solution
The correct option is B1 limx→π4cosx−sinx(π4−x)(cosx+sinx) =limx→π41−tanx(π4−x)(1+tanx).................(dividing the num and deno by cosx) =limx→π4tan(π4−x)(π4−x)=limh→0tanhh=1