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Question

limxπ4cosxsinx(π4x)(cosx+sinx)=

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Solution

The correct option is B 1
limxπ4cosxsinx(π4x)(cosx+sinx)
=limxπ41tanx(π4x)(1+tanx).................(dividing the num and deno by cosx)
=limxπ4tan(π4x)(π4x)=limh0tanhh=1

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