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Question

limx(x+1)10+(x+2)10+....(x+100)10x10+1010

A
0
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B
1
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C
100
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D
20
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Solution

The correct option is D 100
limx(x10+10C1x9+....+1)+(x10+10C1x9(2)+....+1)+....(x10+10C1x9(100)+....+1)x10+1010
Taking x10 common in both numerator and denominator
=limxx10x10(1+10C11x+...1x10)+(1+10C1(2)x+...+1x10)+....(1+10C1(100)x+...+1x10)x10(1+1010x10)
as x1x0
1xn0
=(1+1+.....100 times)1+0=100

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