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Question

limxlog[x]x, where [x] denotes the greatest integer less than or equal to x, is?

A
0
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B
1
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C
1
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D
Non-existent
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Solution

The correct option is A 0
Let x=n+k, where 0<k<1. Then, [x]=n

limxlog[x]x=limnlognn+k

limxlog[x]x=limn1n=0 [Using L' Hospital's Rule]
Hence, option 'A' is correct.

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