Lim x- 1- t 2 x sin k - 1- t 2 x is t- k - R

The correct option is B k x ∞lim(1+t^2)^xsink(1+t^2)^xx =x→∞limK sink(1+t^2)^xk(1+t^2)^x x→∞lim k =k ANSWER IS B ...

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Standard XII

Mathematics

Chain Rule of Differentiation

lim x→∞ 1+ t ...

Question

$lim x \to \infty {(1 + t^{2})}^{x} sin \frac{k}{{(1 + t^{2})}^{x}}$ is $(t, k ϵ R$ )

k^{1 / 2}

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k

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k^{2}

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N o n e o f t h e s e

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Solution

The correct option is B $k$
$l i m x - \infty (1 + t^{2})^{x} sin \frac{k}{(1 + t^{2})^{x}} x$
$= l i m x \to \infty \frac{K sin \frac{k}{(1 + t^{2})^{x}}}{\frac{k}{(1 + t^{2})^{x}}}$
$l i m x \to \infty k$
$= k$
ANSWER IS B

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