The correct option is
C π8As
x→∞,cos(π8x)→1Looking at the rest of the part,
limx→∞π8x→0limx→∞x.sin(π8x)
=limx→∞sin(π8x)1x
We multiply and divide by π8
=limx→∞,sin(π8x)π8x×π8x
Now using the property of a limit,
limy→0,sinyy =1
We get, applying the limit,
=1× π8
= π8