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Question

limxxcos(π8x)sin(π8x)=

A
π
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B
π2
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C
π8
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D
π4
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Solution

The correct option is C π8
As x,cos(π8x)1
Looking at the rest of the part,
limxπ8x0
limxx.sin(π8x)
=limxsin(π8x)1x
We multiply and divide by π8
=limx,sin(π8x)π8x×π8x
Now using the property of a limit,
limy0,sinyy =1
We get, applying the limit,
=1× π8
= π8

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