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Question

limxπ/2(secxtanx) is equal to

A
2
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B
1
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C
1
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D
0
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Solution

The correct option is C 0
limxπ2(secxtanx)
limxπ2(1sinxcosx)(00form)
Using 'L' hospital rule,
limxπ2cosxsinx
=limxπ2cotx=cotπ2=0

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