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Question

limx1{x1x},where{.} denotes the fraction part function

A
is equal to 1
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B
is equal to 0
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C
Does not exist
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D
None of these
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Solution

The correct option is B is equal to 0
limx1{x1x}
Substitute x=1+h
RHL:limh0+{(1+h)1(1+h)}={2.0}=0
Similarly,
LHL:limh0{(1h)1(1h)}={2.0}=0
And, limx1{x1x}={1.011.0}={2.0}=0
Hence option (B) is correct.

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