${log}_{10} 0.01 = - k$ then value of $4 k$ is

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Solution

$10^{- 2} = 0.01$
Taking log on both the sides
$- 2 log 10 = log 0.01$
${log}_{10} 0.01 = - 2$ ...( $∵ {log}_{b} a = \frac{log a}{log b}$ )
k=2
4k=8

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