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Assigning Oxidation Numbers

MnO2s + 4 HCl...

Question

$M n O_{2 (s)} + 4 H C l_{(a q)} H e a t - -- \to M n C l_{2 (a q .)} + 2 H_{2} O + C l_{2 (g)}$
The equivalent weight of $M n O_{2}$ in the above reaction is:

A

23.4

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B

33.6

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C

43.5

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D

53.6

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Solution

The correct option is D 43.5
$M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}$
$∵$ 71 g of $C l_{2}$ is displaced by = 1 mole (M) of $M n O_{2}$
$∴$ 35.5 g of $C l_{2}$ is displaced by
$= \frac{M}{71} \times 35.5 = \frac{M}{2}$ of $M n O_{2}$
$∴$ Equivalent weight of $M n O_{2}$
$= \frac{Molecular mass}{2} = \frac{87}{2} = 43.5$

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Similar questions

Q. Assertion :One equivalent of

M n O_{2}

reacts with 2 equivalents of

H C l

in the reaction,

M n O_{2} + 4 H C l ⟶ M n C l_{2} + 2 H_{2} O + C l_{2}

. Reason: One equivalent of

M n O_{2}

reacts with one equivalent of

H C l

.

{MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)

In the above reaction, which one of them is getting reduced?

{MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)

In the above reaction, which one of them is getting reduced?

M n O_{4}^{2 -}

M n O_{2}

M n O_{4}^{-}

in acidic medium. Calculate equivalent weight of

M n O_{4}^{2 -}

.

${MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)$

Identify the oxidising and reducing agents in the above reaction. Give an example of a decomposition reaction. [3 MARKS]

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