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Question

N2(g)+3H2(g)2NH3(g)+92 kJ

According to the equation above, what mass of nitrogen gas is required to produce 68 g of ammonia?

A
112 g
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B
56 g
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C
44 g
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D
28 g
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E
14 g
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Solution

The correct option is A 56 g
N2(g)+3H2(g)2NH3(g)+92 kilojoules
The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to 6817=4 moles.
2 moles of ammonia are obtained from 1 mole of nitrogen.
4 moles of ammonia are obtained from 4×12=2 moles of nitrogen.
The molar mass of nitrogen is 28 g/mol.
The mass of nitrogen is 2×28=56 grams.
Thus, 56 g of nitrogen gas is required to produce 68 g of ammonia.

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