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Byju's Answer

Standard XII

Chemistry

Limiting Reagent or Reactant

Na 3 PO 4 aq ...

Question

${N a}_{3} {P O}_{4} (a q) + {M g ({N O}_{3})}_{2} (a q) \to$ ${{M g}_{3} ({P O}_{4})}_{2} (s) + N a {N O}_{3} (a q)$

Equal volumes of 0.10 M sodium phosphate and 0.10 M magnesium nitrate are mixed according to the unbalanced reaction equation above. Which of the following statements is true regarding the reaction?

When the reaction is complete, the concentrations of both magnesium and phosphate are essentially 0.

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Magnesium nitrate is the limiting reactant.

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Sodium phosphate is the limiting reactant.

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Since nitrate ion is a spectator ion, the concentration of nitrate ion in the final solution will be the same as in the original magnesium nitrate solution.

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{N a}_{3} {P O}_{4}

and

{M g ({N O}_{3})}_{2}

react in a 1:1 ratio.

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Solution

The correct option is B Magnesium nitrate is the limiting reactant.
$2 N a_{3} P O_{4} + 3 M g (N O_{3})_{2} \to M g_{3} (P O_{4})_{2} + 6 N a N O_{3}$

2 moles of sodium phosphate requires 3 moles of magnesium nitrate

Hence magnesium nitrate is the limiting reactant.

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Similar questions

. . . {N a}_{3} {P O}_{4} (a q) + . . . {M g ({N O}_{3})}_{2} (a q) \to . . . {{M g}_{3} ({P O}_{4})}_{2} (s) + . . . N a {N O}_{3} (a q)

Equal volume of 0.10 M sodium phosphate and 0.10 M magnesium nitrate are mixed in a container according to the above unbalanced reaction equation. After the completion of the reaction, what is the concentration of sodium ions in the solution?

. . . {N a}_{3} {P O}_{4} (a q) + . . . {M g ({N O}_{3})}_{2} (a q) \to . . . {{M g}_{3} ({P O}_{4})}_{2} (s) + . . . N a {N O}_{3} (a q)

Equal volumes of 0.10 M sodium phosphate and 0.10 M magnesium nitrate are mixed in a container according to the above unbalanced reaction equation. Which of the following statements is true regarding the reaction?

Q. Equal volumes of

0.1

{A g N O}_{3}

and

0.2

N a C l

solutions are mixed. The concentration of nitrate ion in the resultant mixture will be:

Q. Write the balanced chemical equation for the following and identify the type of reaction in each case.
a)

{C a l c i u m h y d r o x i d e}_{(a q)} + {N i t r i c a c i d}_{(a q)} \to {W a t e r}_{(l)} + {C a l c i u m n i t r a t e}_{(a q)}

{M a g n e s i u m}_{(s)} + {I o d i n e}_{(g)} \to {M a g n e s i u m i o d i d e}_{(s)}

{M a g n e s i u m}_{(s)} + {H y d r o c h l o r i c a c i d}_{(a q)} \to {M a g n e s i u m c h l o r i d e}_{(a q)} + {H y d r o g e n}_{(g)}

{Z i n c}_{(s)} + {C a l c i u m c h l o r i d e}_{(a q)} \to {Z i n c c h l o r i d e}_{(a q)} + {C a l c i u m}_{(s)}

$P b (N O_{3})_{2} (a q) + 2 K C l (a q) \to 2 K N O_{3} (a q) + P b C l_{2} (s)$

When lead nitrate solution is mixed with potassium chloride solution, a precipitate of lead chloride and potassium nitrate solution are formed. This type of reaction is called _________________.

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Na3PO4(aq)+Mg(NO3)2(aq)→ Mg3(PO4)2(s)+NaNO3(aq)Equal volumes of 0.10 M sodium phosphate and 0.10 M magnesium nitrate are mixed according to the unbalanced reaction equation above. Which of the following statements is true regarding the reaction?

The correct option is B Magnesium nitrate is the limiting reactant.2Na3PO4+3Mg(NO3)2→Mg3(PO4)2+6NaNO32 moles of sodium phosphate requires 3 moles of magnesium nitrateHence magnesium nitrate is the limiting reactant.

The correct option is B Magnesium nitrate is the limiting reactant.
$2 N a_{3} P O_{4} + 3 M g (N O_{3})_{2} \to M g_{3} (P O_{4})_{2} + 6 N a N O_{3}$

2 moles of sodium phosphate requires 3 moles of magnesium nitrate

Hence magnesium nitrate is the limiting reactant.