${N H}_{4} C l$ can be prepared by $({N H}_{4})_{2} {S O}_{4}$ in group III.

If the given statement is true enter 1 else enter 0.

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Solution

The statement " ${N H}_{4} C l$ can be prepared by $({N H}_{4})_{2} {S O}_{4}$ in group III" is false.
${N H}_{4} C l$ is used alongwith ${N H}_{4} O H$ in group III. Ammonium chloride provides common ion (ammonium ion) and decreases ionisation of ${N H}_{4} O H$ . $({N H}_{4})_{2} {S O}_{4}$ also provides ${N H}_{4}$ +ion but it can't be used as ${S O}_{4}^{2 -}$ ion will precipitate ${Z n}^{2 +}, {C a}^{2 +}, {B a}^{2 +} a n d {S r}^{2 +}$ ions as their sulphate.

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