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Oxides and Oxoanions

NH 4 SCN give...

Question

${N H}_{4} S C N$ gives red colour with ${F e}^{3 +}$ Due to the formation of $[{F e (S C N)]}^{2 +}$ .

If the given statement is true enter 1 else 0.

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Solution

${N H}_{4} S C N$ gives red colour with ${F e}^{3 +}$ due to the formation of $[{F e (S C N)]}^{2 +}$ .
$F e C l_{3} + 3 N H_{4} S C N \to F e (S C N)_{3} r e d c o l o u r + 3 N H_{4} C l$

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Q. Reagent that can detect any

{F e}^{3 +}, {C o}^{2 +}

{C u}^{2 +}

{N H}_{4} S C N

If the given statement is true enter 1 else enter 0.

F e^{3 +}

(aq.) reacts with aqueous KSCN to give a deep red solution due to the formation of

[F e (S C N)^{2 +}]

If true enter 1, else enter 0.

Q. Ferric alum gives red colour with

{N H}_{4} S C N

due to formation of:

{A s}_{2} S_{3}

({N H}_{4})_{2} S_{2}

(yellow ammonium sulphide) due to the formation of

({N H}_{4})_{3} {A s S}_{4}

If the given statement is true enter 1 else enter 0.

{N H}_{4} S C N

can be used to make distinction between

{C u}^{2 +}

{C o}^{2 +}

If the given statement is true enter 1 else enter 0.

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