$O_{2}$ undergoes photochemical dissociation into 1 normal oxygen atom (O) and more energetic oxygen $O_{2}$ . If (O) has 1.967 eV more energy than ( $O_{2}$ ) and normal dissociation energy of $O_{2}$ is 498 kJ mol $^{- 1}$ , the maximum wavelength effective for the photochemical dissociation of $O_{2}$ is:

174 nm

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123 nm

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234 nm

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396 nm

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Solution

The correct option is A 174 nm

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Similar questions

O_{2}

undergoes photochemical dissociation into

1

normal oxygen atom (

O

) and more energetic oxygen

O^{*}

. If (

O^{*}

) has

1.967 e V

more energy than (

O

) and normal dissociation energy of

O_{2}

498 k J

{m o l}^{- 1}

, what is the maximum wavelength effective for the photochemical dissociation of

O_{2}

O_{2}

undergoes photochemical dissociation into one normal oxygen atom and one oxygen atom which is 1.5

e V

more energetic than normal. The dissociation of

O_{2}

into two normal atoms of oxygen requires 504

k J m o l^{- 1}

. What is the maximum wavelength effective for photochemical dissociation of

O_{2}

$O_{2}$ undergoes photochemical dissociation into one normal and one excited atoms. The excited atom has 1.967 eV more energy than normal. The dissociation of $O_{2}$ into two normal atoms requires 498 KJ mole-1. Then the maximum wavelength required for photochemical dissociation of $O_{2}$ is