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Stoichiometric Calculations

P4S3+8O2→P4O1...

Question

$P_{4} S_{3} + 8 O_{2 \to} P_{4} O_{10} + 3 S O_{2}$
Calculate minimum mass of $P_{4} S_{3}$ is required to produce at least $0.96$ g of each product.

A

1.1 g

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B

1.5 g

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C

2.3 g

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D

2.8 g

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Solution

The correct option is B $1.1 g$
The molar masses of $P_{4} S_{3}, P_{4} O_{10}$ and $S O_{2}$ are $220$ g/mol, $283.88$ g/mol and $64$ g/mol.
Thus, $220$ g of $P_{4} S_{3}$ will produce $283.88$ g of $P_{4} O_{10}$ and $3 \times 64 = 192$ g of $S O_{2}$ .
The amount of $S O_{2}$ produced is lower than that of $P_{4} O_{10}$ .
Thus, the minimum mass of $P_{4} S_{3}$ that is required to produce atleast $0.96$ g of each product is $\frac{220}{192} \times 0.96 = 1.1 g$ .

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Similar questions

P_{4} O_{10}

440

P_{4} S_{3}

384 g m

O_{2}

P_{4} S_{3} + O_{2} \to P_{4} O_{10} + S O_{2}

Q. The minimum mass of the mixture of

A_{2}

B_{4}

required to produce at least

1 k g

of each product is:
(Given At. mass of

A = 10

B = 120

5 A_{2} + 2 B_{4} ⟶ 2 A B_{2} + 4 A_{2} B

.

Q. The minimum mass of mixture of

A_{2}

B_{4}

required to produce at least

1 k g

of each product is :
(Given Atomic mass of 'A' = 10; At mass of 'B' = 120)

5 A_{2} + 2 B_{4} \to 2 A B_{2} + 4 A_{2} B

5 A_{2} + 2 B_{4} \to 2 A B_{2} + 4 A_{2} B

The minimum mass of mixture of

A_{2}

B_{4}

required to produce at least

1

kg of each product is :

(Given atomic mass of

A = 10, B = 120

)

5 A_{2} + 2 B_{4} \to 2 A B_{2} + 4 A_{2} B

The minimum mass of mixture of

A_{2}

B_{4}

in grams required to produce at least

1 kg

of each product is:
(Given atomic mass of

^{'} A^{'} = 10

; Atomic mass of

^{'} B^{'} = 120

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