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Enantiomers

PbSO 4 is sol...

Question

${P b S O}_{4}$ is soluble in ${C H}_{3} {C O O N H}_{4}$ due to formation of $({C H}_{3} C O O)_{2} P b$ .

If the given statement is true enter 1 else enter 0.

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Solution

${P b S O}_{4}$ is soluble in ${C H}_{3} {C O O N H}_{4}$ due to formation of $({C H}_{3} C O O)_{2} P b$ . .

${P b S O}_{4} + 2 {C H}_{3} {C O O N H}_{4} \to ({C H}_{3} C O O)_{2} P b + (N H_{4})_{2} S O_{4}$

Thus, the given statement is true.

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