Question

$Ph-CHO+HCHO\underset{\Delta }{\overset{KOH}{\to }}$ ( i ) $\underset{\Delta }{\overset{KOH}{\to }}$ (ii) :

Find out (i) and (ii)

• A. (i) $Ph-C{H}_{2}OH$, HCOOH, (ii) $P{h}_{2}C{H}_{2}OOCH$
• B. (i) $Ph-COOH$, $C{H}_{3}OH$ (ii) $Ph-COOC{H}_3$
• C. Both A & B
• D. None Of These.

Answer 1

The correct option is A (i) $Ph-C{H}_{2}OH$, HCOOH, (ii) $P{h}_{2}C{H}_{2}OOCH$

Benzaldehyde and formaldehyde undergo cannizzaro reaction when heated together in presence of KOH. Benzaldehyde is reduced to benzyl alcohol and formaldehyde is oxidized to formic acid. Thus (i) is a mixture of benzyl alcohol and formic acid $PhC{H}_{2}OH+HCOOH$.

When this mixture is heated in presence of KOH, esterification reaction forms benzyl formate $HCOOC{H}_{2}Ph$