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Question

S=n2[2a+(n−1)d]; make d the subject of formula.

A
d=(2Sa)n(n1)
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B
d=(2Sna)n(n+1)
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C
d=2(Sna)n(n1)
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D
d=2(Sa)n(n+1)
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Solution

The correct option is C d=2(Sna)n(n1)
Given, S=n2[2a+(n1)d]
=>2Sn=2a+(n1)d
=>2Sn2a=(n1)d
=>2(Sna)n=(n1)d
=>d=2(Sna)n(n1)

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