S-u-1-2a 2t-1 - make -t- the subject of formula-

The correct option is B t=2 ( s u )+a/2a Given, s = u + 12a(2t 1) ⇒ s u = 1/2a(2t 1) ⇒2(s u)a = 2t 1 ⇒2(s u)a + 1 = 2t ⇒ # ...

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Standard XII

Mathematics

Definition of Functions

s=u+1/2a 2t-1...

Question

$s = u + \frac{1}{2} a (2 t - 1)$ ; make 't' the subject of formula.

t = \frac{(s - u) + a}{2 a}

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t = \frac{2 (s - u) + a}{2 a}

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t = \frac{2 (s - u) - a}{2 a}

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t = \frac{2 (s + u) + a}{2 a}

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Solution

The correct option is B $t = \frac{2 (s - u) + a}{2 a}$
Given, $s = u + \frac{1}{2} a (2 t - 1)$
$\Rightarrow s - u = \frac{1}{2} a (2 t - 1)$
$\Rightarrow \frac{2 (s - u)}{a} = 2 t - 1$
$\Rightarrow \frac{2 (s - u)}{a} + 1 = 2 t$
$\Rightarrow 2 t = \frac{2 (s - u) + a}{a}$
$\Rightarrow t = \frac{2 (s - u) + a}{2 a}$

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s=u+12a(2t−1) ; make 't' the subject of formula.

The correct option is B t=2(s−u)+a2aGiven, s=u+12a(2t−1)⇒s−u=12a(2t−1)⇒2(s−u)a=2t−1⇒2(s−u)a+1=2t⇒2t=2(s−u)+aa⇒t=2(s−u)+a2a

$s = u + \frac{1}{2} a (2 t - 1)$ ; make 't' the subject of formula.