Question

${\sin }^2\theta =\frac{(x+y{)}^2}{4xy}$ is possible only, when

• A. $x>0$, $y>0$ and $x$ $\ne$ $y$
• B. $x>0$, $y>0$ and $x=y$
• C. $x<0$, $y<0$ and $x=y$
• D. $x>0$, $y<0$ and x $\ne$ y

Answer 1

The correct option is B $x>0$, $y>0$ and $x=y$