Question

$\sin ({25}^0+\theta ).\cos ({25}^0-\varphi )-\cos ({25}^0+\theta ).\sin ({25}^0-\varphi )=\sin (\theta +\varphi )$

• A. True
• B. False

Answer 1

The correct option is A True

As we know that

$\sin (A-B)=\sin A\cos B-\cos A\sin B$

$\sin ({25}^{\circ }+\theta )\cos ({25}^{\circ }-\varphi )-\cos ({25}^{\circ }+\theta )\left(\sin \right({25}^{\circ }-\varphi )=\sin ({25}^{\circ }+\theta -({25}^{\circ }-\varphi ))=\sin (\theta +\varphi )$