$\sqrt[3]{[\frac{(- 1728)}{2744}]}$

\frac{- 6}{11}

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\frac{- 6}{7}

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\frac{- 3}{4}

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\frac{- 12}{14}

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Solution

The correct option is C $\frac{- 12}{14}$
$\sqrt[3]{\frac{(- 1728)}{(2744)}}$
$\Rightarrow \sqrt[3]{{(\frac{- 12}{14})}^{3}}$
$\Rightarrow (\frac{- 12}{14})$

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Similar questions

Q. Evaluates the following.

\frac{(- 14)^{4} \times 11^{3} \times 6}{7^{3} \times 12^{2} \times 121}

$(5 + 6 \times 3 - 4) + (5 \times 6) \times (14 - 7) + (12 \div 4 \times 9) = ?$

Q. Evaluate:

\sqrt[3]{\frac{- 1728}{2744}}

Q. 2 6 5 11 : 3 7 8 14 :: 5 12 20 29 : ?

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

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3 ⎷[(−1728)2744]

The correct option is C −12143√(−1728)(2744)⇒3√(−1214)3⇒(−1214)

$\sqrt[3]{[\frac{(- 1728)}{2744}]}$

The correct option is C $\frac{- 12}{14}$
$\sqrt[3]{\frac{(- 1728)}{(2744)}}$
$\Rightarrow \sqrt[3]{{(\frac{- 12}{14})}^{3}}$
$\Rightarrow (\frac{- 12}{14})$