Question

$\sqrt{-35+12i}-\sqrt{-35-12i}=p$

The value of p can be?

• A. $2$
• B. $-12i$
• C. $12i$
• D. $-2$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $2$
B $-12i$
C $-2$
D $12i$

for $\sqrt{-35+12i}$
half of the coefficient of $i$ is $6$ whose factors are $1$ & $6$
Since, $1^2-6^2=-35$
Therefore, $\sqrt{-35+12i}-\sqrt{-35-12i}=\pm (1+6i)-\pm (1-6i)=\pm 12ior\pm 2$
Ans: A,B,C,D