-k - 16 -sin2k-7 - icos2k-7 - -

The correct option is D i i nbsp;∑_k = 1^6 [cos2kπ7 isin2kπ7 ] i[1+α +α^2+...+α^6 1]= i[0 1]=i ...

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Modulus of a Complex Number

∑k = 16 [sin2...

Question

$6 \sum k = 1 [sin \frac{2 k π}{7} - i cos \frac{2 k π}{7}] =$ ?

1

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Similar questions

6 \sum k = 1 [sin \frac{2 k π}{7} - i cos \frac{2 k π}{7}]

6 \sum k = 1 [sin \frac{2 k π}{7} - i cos \frac{2 k π}{7}]

7 \sum k = 1 [sin \frac{2 k Π}{7} - i cos \frac{2 k Π}{7}]

\sum_{k = 1}^{4} [sin \frac{2 k π}{5} - i cos \frac{2 k π}{5}]

\sum_{k = 1}^{6} [sin \frac{2 k π}{7} - ι cos \frac{2 k π}{7}] =

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