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Byju's Answer
Standard X
Mathematics
Relation between Areas and Sides of Similar Triangles
ABC∼ PQR If a...
Question
△
A
B
C
∼
△
P
Q
R
If ar(ABC)=2.25
m
2
ar(PQR)=6.25
m
2
, PQ=0.5 m, then length of AB is
A
30
c
m
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B
1.5
c
m
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C
50
c
m
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D
2
m
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Solution
The correct option is
A
30
c
m
The area of two similar triangles are proportional to the square of their corresponding sides
∴
A
r
(
A
B
C
)
a
r
(
P
Q
R
)
=
(
A
B
)
2
(
P
Q
)
2
⇒
2.25
6.25
=
(
A
B
)
2
(
.5
)
2
⇒
A
B
2
=
2.25
×
.5
6.25
⇒
A
B
2
=
.09
⇒
A
B
=
.3
m
=
30
c
m
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0
Similar questions
Q.
Let
△
ABC ~
△
PQR. If area(ABC) = 2.25
m
2
, area(PQR) = 6.25
m
2
, PQ = 0.5
m
, then length of AB is:
Q.
Given
△
A
B
C
∼
△
P
Q
R
, if
A
B
P
Q
=
1
3
, then find
a
r
(
△
A
B
C
)
a
r
(
△
P
Q
R
)
.
Q.
Δ
A
B
C
∼
Δ
P
Q
R
.
If area
(
A
B
C
)
=
2.25
m
2
, area
(
P
Q
R
)
=
6.25
m
2
,
P
Q
=
0.5
m
, then length of AB is:
Q.
If
△
A
B
C
∼
△
P
Q
R
, then
a
r
(
△
A
B
C
)
a
r
(
△
P
Q
R
)
=
A
C
2
P
Q
2
Q.
If
△
A
B
C
∼
△
P
Q
R
,
a
r
(
A
B
C
)
a
r
(
P
Q
R
)
=
9
4
,
A
B
=
18
c
m
and
B
C
=
15
c
m
, then
Q
R
is equal to:
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