wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

limxax58a58x13a13=

A
158a247
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
815a247
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
158a724
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
815a724
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 158a724

limxax58a58x13a13=a58a58a13a13=00

Above limit is in 00 form.

So, differentiate both numerator and denominator using L'Hospital's rule

limxax58a58x13a13

=limxa58×x58113×x131

=limxa158x5813

=limxa158x724

=158a724


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebra of Continuous Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon