O-A- 3i-4j-12k-O-B- 12i-3j-4k- O-C- 4i-12j-3k- Find the area of triangle OAB-

The correct option is A Δ OAB=12√(19345) O⃗A⃗×O⃗B⃗= | i amp; #160;j amp; k #160;3 amp; #160;4 amp; 12 #160;12 amp; ...

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Definite Integral as Limit of Sum

O⃗A⃗= 3i+4j+1...

Question

$\to O A = 3 i + 4 j + 12 k, \to O B = 12 i + 3 j + 4 k,$ $\to O C = 4 i + 12 j + 3 k .$
Find the area of triangle OAB.

Δ O A B = \frac{1}{2} \sqrt{19345}

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Δ O A B = 19345

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Δ O A B = \frac{1}{2} \sqrt{30085}

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Δ O A B = 30085

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Solution

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Similar questions

\to O A = 3 i + 4 j + 12 k, \to O B = 12 i + 3 j + 4 k,

\to O C = 4 i + 12 j + 3 k .

\to O A

\to O C .

\to O A = 3 i + 4 j + 12 k, \to O B = 12 i + 3 j + 4 k,

\to O C = 4 i + 12 j + 3 k .

\to O A

\to O B

\to O A = 3 i + 4 j + 12 k, \to O B = 12 i + 3 j + 4 k,

\to O C = 4 i + 12 j + 3 k .

13 ¯ ¯ ¯ a = 3 ¯ i + 4 ¯ j + 12 ¯ ¯ ¯ k, 13 ¯ ¯ b = 4 ¯ i - 12 ¯ j + 3 ¯ ¯ ¯ k, 13 ¯ ¯ c = 12 ¯ i + 3 ¯ j - 4 ¯ ¯ ¯ k

¯ ¯ ¯ a \times ¯ ¯ b

\to c

\to O A

\to O B

Δ O A B

∠ A O B

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