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Byju's Answer
Standard XII
Mathematics
Definition of Limit
O⃗A⃗= 3i+4j+1...
Question
→
O
A
=
3
i
+
4
j
+
12
k
,
→
O
B
=
12
i
+
3
j
+
4
k
,
→
O
C
=
4
i
+
12
j
+
3
k
.
Find the unit vector perpendicular to
→
O
A
and
→
O
B
A
20
i
−
132
j
+
39
k
√
(
19345
)
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B
−
20
i
+
132
j
−
39
k
√
(
19345
)
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C
50
−
156
j
+
57
k
√
(
30085
)
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D
−
50
i
+
156
j
−
57
k
√
(
30085
)
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Solution
The correct option is
B
−
20
i
+
132
j
−
39
k
√
(
19345
)
→
O
A
×
→
O
B
=
∣
∣ ∣
∣
i
j
k
3
4
12
12
3
4
∣
∣ ∣
∣
=
−
20
i
+
132
j
−
39
k
∴
Unit vector
⊥
to both
→
O
A
and
→
O
B
=
−
20
i
+
132
j
−
39
k
√
[
(
−
20
)
2
+
(
132
)
2
+
(
−
39
)
2
]
=
−
20
i
+
132
j
−
39
k
√
(
19345
)
Suggest Corrections
0
Similar questions
Q.
→
O
A
=
3
i
+
4
j
+
12
k
,
→
O
B
=
12
i
+
3
j
+
4
k
,
→
O
C
=
4
i
+
12
j
+
3
k
.
Find the angle between
→
O
A
and
→
O
C
.
Q.
→
O
A
=
3
i
+
4
j
+
12
k
,
→
O
B
=
12
i
+
3
j
+
4
k
,
→
O
C
=
4
i
+
12
j
+
3
k
.
Find the area of triangle OAB.
Q.
Find out the volume of a prism on tringular base, the three sides of the prism meeting on a vertex are given below:
→
O
A
=
3
i
+
4
j
+
12
k
,
→
O
B
=
12
i
+
3
j
+
4
k
,
→
O
C
=
4
i
+
12
j
+
3
k
.
Q.
If
13
¯
¯
¯
a
=
3
¯
i
+
4
¯
j
+
12
¯
¯
¯
k
,
13
¯
¯
b
=
4
¯
i
−
12
¯
j
+
3
¯
¯
¯
k
,
13
¯
¯
c
=
12
¯
i
+
3
¯
j
−
4
¯
¯
¯
k
, then the value of
¯
¯
¯
a
×
¯
¯
b
in terms of
→
c
is
Q.
Let
→
O
A
=
ˆ
i
+
3
ˆ
j
−
2
ˆ
k
and
→
O
B
=
3
ˆ
i
+
ˆ
j
−
2
ˆ
k
, then the vector
→
O
C
bisecting the
∠
A
O
B
and
C
being a point on the line
A
B
is
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