R-1-2k- 3-2-4k- r-2-2-3k- - 6-4-8k-

r⃗_⃗1⃗ nbsp;is parallel to nbsp; 3î 2ĵ + 4k̂ r⃗_⃗2⃗ nbsp;is parallel to nbsp; 6î + 4ĵ 8k̂ Hence, nbsp; r⃗_⃗2⃗ = 2r⃗_⃗1⃗ ...

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Number Line

r⃗⃗1⃗=î+ĵ+2k̂...

Question

$_{1} =^i +^j + 2^k + λ (3^i - 2^j + 4^k)$
$_{2} = 2^i +^j + 3^k + μ (- 6^i + 4^j - 8^k)$

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Solution

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_{1} =^i +^j + 2^k + λ (3^i - 2^j + 4^k)

_{2} = 2^i +^j + 3^k + μ (- 6^i + 4^j - 8^k)

_{1} =^i -^j + 3^k + λ (^i -^j +^k)

_{2} = 2^i + 4^j + 6^k + μ (2^i +^j + 3^k)

_{1} = 2^i + 4^j,_{2} =^i + 4^j - 2^k

_{3} =^i +^j +^k

_{3}

_{1},_{2}

_{1} =^i +^k + λ (^i + 3^j + 4^k)

_{2} = 2^i + 3^j + μ (4^i -^j +^k)

_{1} = (^i + 2^j - 3^k) + s (3^i +^j -^k)

_{2} = (4^i +^j -^k) + t (2^i -^j + 3^k)

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