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Question

x2+y2+6x+8y11=0 ( chord of contact)

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Solution

For x2+y2+2gx+2fx+c=0
Chord of contact from (x1,y1) is
xx1+yy1+g(x+x1)+f(y+y1)+c=0
So, for x2+y2+6x+8y11=0
Chord of contact from (x1,y1) is
xx1+yy1+3(x+x1)+4(y+y1)11=0
1) For (1,1), equation is
x.1+y.1+3(x+1)+4(y+1)11=04x+5y4=0
2) For (0,0), equation is
x.0+y.0+3(x+0)+4(y+0)11=03x+4y11=0
3) For (1,1), equation is
x.1+y.1+3(x+1)+4(y1)11=04x+3y12=0
4) For (1,1), equation is
x.1+y.1+3(x1)+4(y1)11=02x+3y18=0

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