X - R - 2x - 1-x3 - 4x2 - 3x - R Equals

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Graph of Quadratic Expression

x ϵ R : 2x ...

Question

$x ϵ R : \frac{2 x - 1}{x^{3} + 4 x^{2} + 3 x} ϵ R$ Equals

R - {0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R - {0, 1, 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R - {0, - 1, - 3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

R - 0, - 1, - 3, + \frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $R - {0, - 1, - 3}$
For the equation to take all real values denominator must not be equal to zero

$\Rightarrow x^{3} + 4 x^{2} + 3 x \neq 0$

$\Rightarrow x (x^{2} + 4 x + 3) \neq 0$

$\Rightarrow x (x + 3) (x + 1) \neq 0$

$\Rightarrow x \neq 0, x \neq - 1, x \neq - 3$

Answer is $R - {0, - 1, - 3}$

Suggest Corrections

Similar questions

Applying the following transformations will result in on the matrix in order on the matrix in order $⎡ ⎢ ⎣ \begin{matrix} 1 & 5 & 2 3 & 1 & 4 2 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦$

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 5 & 2 3 & 1 & 4 2 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦

The following elementary transformations are applied on the matrix A in the given order. The resultant matrix after the following operations

R_{2}

\to

R_{2}

–

R_{3}

R_{1}

\to

R_{1} - R_{2}

R_{3}

\to

R_{3}

– 2

R_{2}

Q. The line x = 0 divides the area enclosed by the curves

| x - 1 | - y = 0, | x | + y - 3 = 0

into two area

R_{1}

and

R_{2}

where

R_{1} < R_{2}

. Then the ratio of

R_{1}

and

R_{2}

Q. Let

f =

R \to R

be a continuous function defined by

f (x) = \frac{1}{e^{x} + 2 e^{- x}}

Statement 1 :

f (c) = \frac{1}{3}

, for some

c ϵ R

Statement 2 :

0 < f (x) \leq \frac{1}{2 \sqrt{2}}

, for all

x ϵ R

Q. A uniformly charged solid sphere or radius

R

has potential

V_{0}

(measured with respect to

\infty

) on its surface. For this sphere, the equipotential surfaces with potentials

\frac{3 V_{0}}{2}, \frac{{5 V}_{0}}{4}, \frac{3 V_{0}}{4}, \frac{V_{0}}{4}

have radius

R_{1}, R_{2}, R_{3}

and

R_{4}

respectively. Then

Join BYJU'S Learning Program

xϵR:2x−1x3+4x2+3xϵR Equals

The correct option is C R−{0,−1,−3}For the equation to take all real values denominator must not be equal to zero⇒x3+4x2+3x≠0⇒x(x2+4x+3)≠0⇒x(x+3)(x+1)≠0⇒x≠0,x≠−1,x≠−3Answer is R−{0,−1,−3}

$x ϵ R : \frac{2 x - 1}{x^{3} + 4 x^{2} + 3 x} ϵ R$ Equals