Question

$x=\frac{4}{3}$ is a root of equation $x^2-\frac{16}{9}=0$

• A. Yes
• B. No
• C. Can't possible
• D. None

Answer 1

The correct option is A Yes

$x^2-\frac{16}{9}=0,(x+\frac{4}{3})(x-\frac{4}{3})=0$
Since,$[(a+b)(a-b)=a^2-b^2]$
$x=\frac{-4}{3}and\frac{4}{3}$ are the roots of $x^2-\frac{16}{9}=0$