P4 +3NaOH + 3H2O⟶′Q′PH3+3NaH2PO2Moles of phosphorous=1.24/124=0.01molSince 1 mol of P forms 1 mol of PH3, 0.01 mol of P will form 0.01 mol of PH32PH3 +3CuSO4⟶Cu3P2+3H2SO4
No. of moles of CuSO4 required to consume 2 mol of phosphine (Q) = 3
So, no. of moles of CuSO4 required to consume 0.01 mol of phosphine (Q) =
(32×0.01) mol
Molar mass of CuSO4=159 g/mol
Mass of CuSO4=(32×0.01)×159=2.385 g