Distance between $(2, 3)$ and $(4, 1)$ is ____

2 \sqrt{2}

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4 \sqrt{2}

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\sqrt{4}

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\sqrt{52}

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Solution

The correct option is A $2 \sqrt{2}$
Given, $A (x_{1}, y_{1}) = (2, 3), B (x_{2}, y_{2}) = (4, 1)$
Using distance formula,
$L_{1} = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$
$= \sqrt{(4 - 2)^{2} + (1 - 3)^{2}}$
$= \sqrt{4 + 4}$
$= \sqrt{8}$
$= 2 \sqrt{2}$
Therefore, distance between points $(2, 3)$ and $(4, 1)$ is $2 \sqrt{2}$ units.

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Distance between (2,3) and (4,1) is ____

The correct option is A 2√2Given, A(x1,y1)=(2,3),B(x2,y2)=(4,1)Using distance formula,L1=√(x2−x1)2+(y2−y1)2=√(4−2)2+(1−3)2=√4+4=√8=2√2Therefore, distance between points (2,3) and (4,1) is 2√2 units.

Distance between $(2, 3)$ and $(4, 1)$ is ____