Distance between a frog and an insect on a horizontal plane is 9 m- Frog can jump with a maximum speed of -10 m-s - Minimum number of jumps required by the frog to catch the insect is Take g - 10 m - s2

Range is maximum for 45^∘ projection The distance covered in one hop will be, R = u^2/g=1 m Hence, it would take 9 jumps ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Range

Distance betw...

Question

Distance between a frog and an insect on a horizontal plane is $9 m$ . Frog can jump with a maximum speed of $\sqrt{10} m / s$ . Minimum number of jumps required by the frog to catch the insect is (Take $g = 10 m / s^{2}$ )

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
9

Range is maximum for $45^{\circ}$ projection

The distance covered in one hop will be, R = $\frac{u^{2}}{g}$ =1 m
Hence, it would take 9 jumps

Suggest Corrections

Similar questions

Distance between a frog and an insect on a horizontal plane is $9 m$ . Frog can jump with a maximum speed of $\sqrt{10} m / s$ . Minimum number of jumps required by the frog to catch the insect is (Take $g = 10 m / s^{2}$ )

Q. The distance between a frog and an insect is

12 m

on a horizontal surface. The frog can jump with a maximum speed of

\sqrt{10} m/s

. The minimum number of jumps required by the frog to catch the insect is

[

Take

g = 10 {m/s}^{2}

]

Q. The distance between a frog and an insect is

12 m

on a horizontal surface. The frog can jump with a maximum speed of

\sqrt{10} m/s

. The minimum number of jumps required by the frog to catch the insect is

[

Take

g = 10 {m/s}^{2}

]

Q. A frog needs to catch an insect that is at a distance of 15 units. If the frog jumps 3 times to catch the insect, what is the suitable expression for this?

Join BYJU'S Learning Program

Distance between a frog and an insect on a horizontal plane is 9 m. Frog can jump with a maximum speed of √10 m/s . Minimum number of jumps required by the frog to catch the insect is (Take g=10 m/s2)

The correct option is C 9 Range is maximum for 45∘ projection The distance covered in one hop will be, R = u2g=1 m Hence, it would take 9 jumps

Distance between a frog and an insect on a horizontal plane is $9 m$ . Frog can jump with a maximum speed of $\sqrt{10} m / s$ . Minimum number of jumps required by the frog to catch the insect is (Take $g = 10 m / s^{2}$ )

The correct option is C
9

Range is maximum for $45^{\circ}$ projection

The distance covered in one hop will be, R = $\frac{u^{2}}{g}$ =1 m
Hence, it would take 9 jumps