Distance between a frog and an insect on a horizontal plane is 9 m- Frog can jump with a maximum speed of -10 m-s - Minimum number of jumps required by the frog to catch the insect is Take g - 10 m - s2

Range is maximum for 45^∘ projection The distance covered in one hop will be, R = u^2/g=1 m Hence, it would take 9 jumps ...

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Standard XIII

Physics

Range

Distance betw...

Question

Distance between a frog and an insect on a horizontal plane is $9 m$ . Frog can jump with a maximum speed of $\sqrt{10} m / s$ . Minimum number of jumps required by the frog to catch the insect is (Take $g = 10 m / s^{2}$ )

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Solution

The correct option is C
9

Range is maximum for $45^{\circ}$ projection

The distance covered in one hop will be, R = $\frac{u^{2}}{g}$ =1 m
Hence, it would take 9 jumps

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Distance between a frog and an insect on a horizontal plane is 9 m. Frog can jump with a maximum speed of √10 m/s . Minimum number of jumps required by the frog to catch the insect is (Take g=10 m/s2)

The correct option is C 9 Range is maximum for 45∘ projection The distance covered in one hop will be, R = u2g=1 m Hence, it would take 9 jumps

Distance between a frog and an insect on a horizontal plane is $9 m$ . Frog can jump with a maximum speed of $\sqrt{10} m / s$ . Minimum number of jumps required by the frog to catch the insect is (Take $g = 10 m / s^{2}$ )

The correct option is C
9

Range is maximum for $45^{\circ}$ projection

The distance covered in one hop will be, R = $\frac{u^{2}}{g}$ =1 m
Hence, it would take 9 jumps