Distance between Bholu's and Golu's house is 9 km. Bholu has to attend Golu's birthday party at 7 pm. He started from his home at 6 pm on his bicycle and covered the distance 6 km in 40 minutes. At that point, he met Chintu and he spoke to him for 5 minutes and reached Golu's birthday party at 7 pm. With what speed did he cover the second part of journey? Calculate his average speed for his entire journey?

Open in App

Solution

It is given that Bholu has to attend the party at 7 pm

Total time spend by Bholu = 40 min (travelling) + 5 min (chatting) = 45 min

So Bholu has to reach Golu’s house within 15 min (1 hour – 45 min)

The speed with which Bholu has to cover the second part of the journey is;
Speed = 3 km/15 min
and we know that, 60 mins = 1 hr
then, 1 min = 1/60 hr
so, 15 min = 15/60 hr
thus, speed in km/h = $\frac{3 \times 60}{15} k m / h = 12 k m / h r$

The average speed of Bholu in the entire journey is total distance divided by the total time taken.

Average speed =Total distance travelled / Total time taken

= 9 km/h

Suggest Corrections

Similar questions

A scooter is has to cover a distance of 10km.He covers the first 4km at a speed of 40km/h.How fast should he run his scooter for remaining journey,such that his average speed for entire journey is 60km/h?

Q. Golu started from his house towards North. After covering a distance of 8 km. he turned towards left and covered a distance of 6 km. What is the shortest distance now from his house?

Q. A man cycles to his office from his house at a speed of 5 km/h and reaches 10 minutes late. If he cycles at a speed of 6 km/h, he reaches 10 minutes early. What is the distance between the office and his house?

Q. A man covers a certain distance between his house and office on a Scooter.Having an average speed of 30 km/hr, he reaches office late by 10 minutes.However,with a speed of 40 km/hr, he reaches his office 5 minutes earlier.the distance between his house and office is

A man walks from his house to his dougther's school at a speed of $3$ km/hr and return back at speed of $4$ km/hr. If he takes $21$ minutes for the double journey; find the distance between his house and the school.

Join BYJU'S Learning Program